Reconstruction Conjecture — Edge Count #
We prove that the number of edges is a reconstructible graph invariant: if two graphs on the same finite vertex set (≥ 3 vertices) have the same deck, they have the same number of edges.
Main results #
SimpleGraph.deleteVert_edgeFinset_card_add_degree—|E(G - v)| + deg(v) = |E(G)|SimpleGraph.degree_eq_card_edgeFinset_sub_deleteVert—deg(v) = |E(G)| - |E(G-v)|SimpleGraph.sum_card_edgeFinset_deleteVert_add—∑ v, |E(G-v)| + 2|E(G)| = n · |E(G)|SimpleGraph.sum_card_edgeFinset_deleteVert—∑ v, |E(G-v)| = (n - 2)|E(G)|SimpleGraph.SameDeck.card_edgeFinset_eq— same deck → same edge count
References #
- Kelly, P. J. (1942). "On isometric transformations".
Deleting vertex v removes exactly deg(v) edges:
|E(G - v)| + deg_G(v) = |E(G)|.
The degree of a deleted vertex is the difference between the original edge count and the edge count of its vertex-deleted card.
Summing the per-vertex edge count formula over all vertices:
∑ v, |E(G - v)| + 2|E(G)| = |V| · |E(G)|.
Equivalently, each edge appears in exactly |V| - 2 of the |V| cards.
The deck-sum edge count formula:
∑ v, |E(G-v)| = (|V| - 2) * |E(G)|.
Thus, for graphs with at least three vertices, the original edge count is recoverable from the multiset of vertex-deleted cards.
Edge count is reconstructible. If two graphs on ≥ 3 vertices have the same deck, they have the same number of edges.
This is a consequence of Kelly's counting lemma: each edge appears in
exactly n - 2 of the n vertex-deleted subgraphs.