An AND-gate lower bound for crown-graph collision #
The crown graph on two copies of Fin N joins a left vertex to a right vertex
exactly when their labels differ. Its graph-collision function asks whether
some marked left vertex and some marked right vertex are adjacent.
On assignments marking exactly one vertex on each side, graph collision is
Boolean inequality. Pulling the positive-generator set problem back to this
one-hot slice therefore gives Neq.problem N exactly, and the inequality
lower bound transfers to monotone AND/OR circuits computing graph collision.
The positive-generator set problem for crown-graph collision.
Equations
Instances For
Mark exactly the two vertices selected by an ordered left/right pair.
Equations
- Algebraic.Fusion.CrownCollision.oneHotPair edge i = Fin.addCases (fun (left : Fin N) => decide (left = edge.1)) (fun (right : Fin N) => decide (right = edge.2)) i
Instances For
Pulling crown-graph collision back to one-hot left/right assignments gives the row/column inequality problem exactly.
Every AND/OR circuit computing crown-graph collision on two copies of
Fin (2 ^ n) uses at least n AND gates, even when OR gates are free.