Angle sums in a star: proofs #
Vectors are functions ι → ℝ with the dot product ∑ i, y i * x i.
arccosis concave on[0, 1], since its derivative-1 / √(1 - x²)is antitone on(0, 1).- Jensen's inequality with uniform weights on a nonempty family, followed by antitonicity of
arccos, bounds thearccos-sum of a family in[0, 1]whose arguments average at leastx₀. - In a star of three, every ordered-pair inner product lies in
[4κ - 3, 1] ⊆ [0, 1], and the six of them sum to at least9κ² - 3by the star inequality.
theorem
Algebraic.Cutwidth.Gaussian.Internal.concaveOn_arccos :
ConcaveOn ℝ (Set.Icc 0 1) Real.arccos
arccos is concave on [0, 1].
theorem
Algebraic.Cutwidth.Gaussian.Internal.sum_arccos_star_le
{ι J : Type}
[Fintype ι]
[DecidableEq J]
{x : ι → ℝ}
(hx : ∑ i : ι, x i ^ 2 = 1)
(s : Finset J)
(hs : s.card = 3)
(y : J → ι → ℝ)
(hy : ∀ j ∈ s, ∑ i : ι, y j i ^ 2 = 1)
{κ : ℝ}
(hκ : 7 / 8 ≤ κ)
(hyx : ∀ j ∈ s, κ ≤ ∑ i : ι, y j i * x i)
:
∑ j ∈ s, ∑ j' ∈ s.erase j, Real.arccos (∑ i : ι, y j i * y j' i) ≤ 6 * Real.arccos ((3 * κ ^ 2 - 1) / 2)
Angles in a star of three. Three unit vectors with inner product at least κ ≥ 7/8
with a unit vector have arccos-sum over the six ordered pairs at most
6 arccos ((3 κ² - 1) / 2).