Sheppard's crossing bound: proofs #
- Planar angle law. In polar coordinates
(r, θ)the product of two standard Gaussians has densityexp (-r²/2) / (2π), and forr > 0the event|x| ≤ k |y|depends onθalone: it holds on the two arcs of(-π, π)of half-widtharctan kcentered at±π/2. The radial factorr exp (-r²/2)integrates to one, so the event has probability4 arctan k / (2π). - Anderson's inequality on the line. For a centered Gaussian,
[c - w, c + w]has at most the mass of[-w, w]. By symmetry takec ≥ 0; the intervals share[c - w, w], and translation by2wcarries[-w, c - w]onto[w, c + w]without increasing the density. - Sheppard's bound. The forms
U = form (α + β)andV = form (β - α)are independent centered Gaussians, and a crossing forces|U - 2t| ≤ |V|. Conditioning onV, Anderson's inequality removes the shift2t. RescalingUandVto standard Gaussians turns|U| ≤ |V|into the planar angle event withk = ‖β - α‖ / ‖α + β‖. - Half-angle identity.
y = tanHalf xhascos (2 arctan y) = (1 - y²) / (1 + y²) = xand0 ≤ 2 arctan y < π, so2 arctan y = arccos x.
The planar angle law #
The standard planar Gaussian density in polar coordinates.
The angles in (-π, π) with |cos θ| ≤ k |sin θ| form two arcs centered at ±π/2.
Planar angle law for the product of two standard Gaussians.
Symmetric intervals carry the most mass #
If translating by 2w does not increase f to the right of -w, then the
interval of radius w around c ≥ 0 carries at most the mass of the centered one.
The centered Gaussian density is even.
One-dimensional Anderson inequality. For a centered Gaussian, an interval of
radius w carries the most mass when it is centered at the mean.
Anderson's inequality for the event |X - c| ≤ |Y| with X, Y independent
and X centered Gaussian.
gaussianReal 0 s is the image of the standard Gaussian under x ↦ √s x.
Planar angle law for two independent centered Gaussians of variances s > 0
and r.
Sheppard's bound #
2 arctan (tanHalf x) = arccos x.