Actual states and transcripts of repeated affine rounds #
Each state keeps the original left and right latent variables. A transition only observes the actual round messages, conditions the corresponding kernels, and computes the next row contributions. The original source maps are lifted along the previous-transcript projection. No new randomness, probability certificate, or extraction guarantee is part of a state.
The deterministic row iteration follows Chattopadhyay--Liao, Extractors for Sum of Two Sources, Theorem 6.1, printed pp.23--25: https://arxiv.org/abs/2110.12652.
Iterate actual rounds, rereading the same original source words at every step.
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- Algebraic.Cutwidth.Extractor.affineRoundsOutput n d h L e 0 x✝² x✝¹ x✝ = x✝
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Forget exactly the five observations added during one round.
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- Algebraic.Cutwidth.Extractor.affineRoundOrigin z = z.1.1.1.1.1
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The complete finite transcript after a specified number of actual rounds.
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Finite initial transcripts remain finite under every finite number of observations.
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Project the complete accumulated transcript to its original tag.
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Actual factors and side maps, with both original latent state spaces unchanged.
- weight : Z → ℝ
The current transcript's marginal weight.
- left : Z → A → ℝ
The conditional weighting of the original left latent variable.
- right : Z → B → ℝ
The conditional weighting of the original right latent variable.
The original left source word at the current transcript.
The original right contribution to the masked left source word.
- rightWords : Z → B → AffinePhaseOneCopies t d
All original right words, with the honest copy indexed by
none. - leftRows : Z → A → AffinePhaseOneCopies t (matchedBlockOutputBits h L)
The current long rows' original-left contributions.
- rightRows : Z → B → AffinePhaseOneCopies t (matchedBlockOutputBits h L)
The current long rows' original-right contributions.
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Execute one round's actual observations and next-row computations.
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The actual evolving factor state after a fixed number of rounds.
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The complete transcript computed from one fixed original pair of latent states.
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- s.transcript e 0 x✝ = x✝.1.1
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Reindex the original law by its actual transcript without discarding either latent state.
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Evolve the original-left joint envelope by the actual message probabilities.
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- s.leftEnvelope e μ 0 = μ
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Evolve the original-right joint envelope through the same actual observations.
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- s.rightEnvelope e ν 0 = ν
- s.rightEnvelope e ν i.succ = Algebraic.Cutwidth.Extractor.affineRoundTranscriptRightEnvelope h t L e (s.rightEnvelope e ν i) (s.iterate e i).left (s.iterate e i).leftRows